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Convert sparse matrix to full matrix
A = full(S)
A = full(S)
converts a sparse matrix S to full storage organization. If S is a full matrix, it is left unchanged. If A is full, issparse(A) is 0.
Let X be an m-by-n matrix with nz = nnz(X) nonzero entries. Then full(X) requires space to store m*n real numbers while sparse(X) requires space to store nz real numbers and (nz+n) integers.
On most computers, a real number requires twice as much storage as an integer. On such computers, sparse(X) requires less storage than full(X) if the density, nnz/prod(size(X)), is less than one third. Operations on sparse matrices, however, require more execution time per element than those on full matrices, so density should be considerably less than two-thirds before sparse storage is used.
Here is an example of a sparse matrix with a density of about two-thirds. sparse(S) and full(S) require about the same number of bytes of storage.
S = sparse(rand(200,200) < 2/3); A = full(S); whos Name Size Bytes Class A 200X200 320000 double array (logical) S 200X200 318432 sparse array (logical)
sparse Create sparse matrix